What is the doll's approximate velocity when the spring once again reaches its relaxation point?

A jack-in-the-box consists of a 100-g doll sitting on top of a spring with a spring constant of 200 N/m. The spring must be compressed 20 cm from its natural length in order to force the doll into the box. If the box is opened, cause the doll to pop out, what is the doll's approximate velocity when the spring once again reaches its relaxation point? (neglect the effects of friction, gravity, and the spring's mass.)|||So we have m= 0.001kg and k= 200N/m and x=0.2m



Using F=kx we can deduce that the Force the spring ejects the doll is:



F = 200N/m *0.2m = 40N



Using F=ma to find the acceleration...

Then you need to work out the time taken for the spring to relax and then apply that t=x to a=v/t



longgggg|||So we have m= 0.001kg and k= 200N/m and x=0.2m





Using F=kx we can deduce that the Force the spring ejects the doll is:





F = 200N/m *0.2m = 40N





Using F=ma to find the acceleration...


Then you need to work out the time taken for the spring to relax and then apply that t=x to a=v/t